Physics, asked by JANSARAPPA9813, 11 months ago

The following circut represents
(a) OR gate (b) XOR gate
(c) AND gate (d) NAND gate

Answers

Answered by CunningKing
0

QUESTION :-

The following circut represents

(a) OR gate (b) XOR gate

(c) AND gate (d) NAND gate

SOLUTION :-

(b) XOR gate

EXPLANATION :-

Substitute all the possible values in place of A and B and form the truth table and then compare the truth table with the truth table of the options given.

Output of upper AND gate = \sf{\dfrac{}{A}}B

Output of lower AND gate = A\sf{\dfrac{}{B} }

Thus, output of OR gate =  \sf{\dfrac{}{A}}B + A\sf{\dfrac{}{B} }

→ This is Boolean expression for XOR gate.

The truth table for the above circuit is :-

00-0

01-1

10-1

11-0

Attachments:
Answered by Anonymous
9

\large\underline\bold{ANSWER \red{\huge{\checkmark}}}

\huge{\underline\bold{OPTION:- B \:\: \huge{\red{\checkmark}}}}

EXPLANATION :-

Substitute all the possible values in place of A and B and form the truth table and then compare the truth table with the truth table of the options given.

Output of upper AND gate = \sf{\dfrac{}{A}}B

Output of lower AND gate = A\sf{\dfrac{}{B} }

Thus, output of OR gate =  \sf{\dfrac{}{A}}B + A\sf{\dfrac{}{B} }

→ This is Boolean expression for XOR gate.

The truth table for the above circuit is :-

00-0

01-1

10-1

11-0

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