The following data are needed for this question. (P4O10(s)) = –3012 kJ mol–1 (H2O(l)) = –286 kJ mol–1 (H3PO4(s)) = –1279 kJmol–1 What is ∆Ho for the reaction shown? P4O10(s) + 6H2O(l) → 4H3PO4(s)A –9844 kJ mol–1 B –388 kJ mol–1 C –97 kJ mol–1 D +2019 kJ mol
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