Math, asked by yasshowardhan, 5 months ago

The following data gives the information in the observed lifetimes (in hours) of 225 electrical
components. Determine the modal lifetime of the component.
Lifetime 0-20 20040 40-60 60-80 80- 100 100-120
in hours
Frequency
15
15
20
23
1
11​

Answers

Answered by rajbirsingh0610
0

Step-by-step explanation:

Lifetime

(in hours) No. of components

0-20 10

20-40 35

40-60 52

60-80 61

80-100 38

100-120 29

As frequency is maximum for the class 60−80, modal class is 60−80.

Mode=l+

2f

1

−(f

0

+f

2

)

f

1

−f

0

×h

where,

l = lower limit of modal class =60

f

1

= frequency of modal class =61

f

0

= frequency of class preceding the modal class =52

f

2

= frequency of class succeding the modal class =38

h= higher limit - lower limit =80−60=20

Mode=60+

2×61−(52+38)

61−52

×20

⇒mode=60+

32

9

×20=60+5.625=65.625

Hence, the modal lifetimes of the components are 65.625 hrs.

hope it helped you

mark me as brainlist

Answered by DevilHunter001
0

Answer:

Step-by-step explanation:

Lifetime

(in hours) No. of components

0-20 10

20-40 35

40-60 52

60-80 61

80-100 38

100-120 29

As frequency is maximum for the class 60−80, modal class is 60−80.

Mode=l+

2f

1

−(f

0

+f

2

)

f

1

−f

0

×h

where,

l = lower limit of modal class =60

f

1

= frequency of modal class =61

f

0

= frequency of class preceding the modal class =52

f

2

= frequency of class succeding the modal class =38

h= higher limit - lower limit =80−60=20

Mode=60+

2×61−(52+38)

61−52

×20

⇒mode=60+

32

9

×20=60+5.625=65.625

Hence, the modal lifetimes of the components are 65.625 hrs.

hope it helped you

mark me as brainlist

Similar questions