The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:
Lifetimes (in hours):
0-20
20-40
40-60
60-80
80-100
100-120
No of components:
10
35
52
61
38
29
Determine the modal lifetimes of the components.
Answers
Answered by
265
SOLUTION :
Mode = l + (f1-f0/2f1-f0-f2) ×h
l = lower limit of the modal class
h = size of the class intervals
f1 = frequency of the modal class
f0 = frequency of the class preceding the modal class
f2 = frequency of the class succeed in the modal class.
FREQUENCY DISTRIBUTION TABLE is in the attachment
Here the maximum frequency is 61, and the class corresponding to this frequency is 60 – 80. So the modal class is 60 - 80.
Therefore,l = 60 , h = 80 – 60 = 20, f1 = 61, , f0 = 52, f2 = 38
Mode = l + [(f1- f0) / (2f1- f0 - f2)] ×h
= 60 + [(61 - 52)/(2 × 61 - 52 – 38) ]×20
= 60 +[(9 × 20)/(122 - 90)]
= 60 + [180/32]
= 60 + 5.625
= 65.625 hours
Hence, the modal lifetimes of the components is 65.625 hours
HOPE THIS ANSWER WILL HELP YOU…
Attachments:
sreenish:
superb explained
Answered by
118
Frequency table ⬆️⬆️ Attachment.
Modal class =
▶️60−80=60-80
▶️l =60
▶️ f1=61
▶️ f 0=52
▶️ f2=38
▶️h=20
=> 65.62
Therefore the Answer is 65.62.
Modal class =
▶️60−80=60-80
▶️l =60
▶️ f1=61
▶️ f 0=52
▶️ f2=38
▶️h=20
=> 65.62
Therefore the Answer is 65.62.
Attachments:
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