Physics, asked by ravikant12233, 2 days ago

The following data is collected from a boiler trial. Feed water = 680 kg/hr at 20°C. Steam generated at 15 bar and 300°C. Coal used=95 kg/hr with C.V.= 26.5 MJ/kg. Ash and unburned coal collected=4 kg/hr whose C.V.- 2.2 MJ/kg. Flue gas formed = 18 kg per kg of coal. Flue gas temp. 300°C and ambient temp = 28°C. Take C 1.025 kJ/kg-"C. Determine (a) Boiler efficiency (b) Equivalent evaporation from and at 100°C. (c) % of unaccounted heat (d) Draught produced in em of water if the chimney height = 50 m.​

Answers

Answered by gaganpreetnaman48
0

Answer:

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Answered by mindfulmaisel
2

Boiler efficiency is 71%

Explanation:

(a) Heat supplied to the boiler per hour = 95 x 26500

                                                                 = 25,17,500

At 8 bar, h = 721-1 kJ/kg, L = 2,048 kJ/kg (from steam tables)

Enthalpy of wet steam,

H1= hy * xL1

= 721-1 + 0-97 x 2,048

= 2,707.67 kJ/kg'

Enthalpy of feed water at 20°C,  = 20 x 4.187 = 83.74 kJ/kg

Heat utilised in steam formation per hour

= mass of steam produced per hr. x (H1 - h2)

= 680(2,707.67 - 83.74)

= 17,84,272.4kJ/hr

Boiler efficiency =  Heat utilized in steam formation per hr./Heat supplied

                           =  17,84,272.4/25,17,500

                           = 0.708

                        = 70.8%

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