Question

The following data is given for copper
(i) Density = 8.92x10 kg/m
(ii) Resistivity = 1.73x10-82m
(iii) Atomic weight = 63.5
Calculate the mobility and average collision time of electrons.​

Answer 1

Explanation:

Density = 8.92x10 kg/m

(ii) Resistivity = 1.73x10-82m

(iii) Atomic weight = 63.5

Answer 2

Given,

          Density (d) = $8.92$×$10^{3} kg/m^{-3}$

          Resistivity (p) = $1.73$×$10^{8} m$

          Atomic weight (A) = $63.5 kg$

To Find: The mobility and average collision time of electrons?

Explanation:

We know the carrier concentration,

The conductivity of copper(n) = (Avagadro number × Density) ÷ Atomic wt.

                                             (n) = {($6.023$×$10^{23}$)×($8.92$×$10^{3}$)} ÷ $63.5$

                                             (n) = $8.46$×$10^{25} m^{-3}$

The electrical conductivity (σ) = 1/p = $1$/$(1.73$×$10^{8}$$)$

                                                 = $5.78$×$10^{-9} ohm^{-1} m^{-1}$

we know,

                                             (σ) = $\frac{ne^{2} }{m}$× τ

average time collision,

                                     τ = σ$m$/$ne^{2}$

                                        = [($5.78$×$10^{-9}$)×($9.11$×$10^{-31}$)] ÷ [($8.46$×$10^{25}$)×($1.6$×$10^{-19}$)^2]

                                      τ = $2.380$×$10^{-27} sec$

Mobility,

                                       μ = σ/$ne$

                                          = ($5.78$×$10^{-9}$) ÷ [($8.46$×$10^{25}$)×($1.6$×$10^{-19}$)]

                                       μ = $4.27 m^{2} V^{-1} s^{-1}$

                                       μ = $4.27$×$10^{-16} m^{2} V^{-1} s^{-1}$