Question

The following data represents 1500 families with 2 children
Find the probability of getting
A) at most 1 girl
B) at least 2 girls

I want accurate answers because last time I asked this question and got answers that didn’t even match the question....

Answer 1

$\rm A. \bigg) \: \: \: \: \: \: \: \frak{ \frac{814 + 211}{1500} = \frac{1025}{1500} = \red{ 0.683}}$

$\rm B. \bigg) \: \: \: \: \: \: \: \frak{ \frac{475}{1500} = \red{ 0.3167}}$

Answer 2

Answer:

A. At most 1 girl = 814/1500

= 407/750

B. At least 2 girls = 475/1500

= 19/60