Question

The following data was obtained on performing an experiment for determining the percentage of water absorbed by raisins
Mass of water in the beaker
=
50 g
Mass of dry raisins
=
20 g
Mass of raisins after soaking in water
=
30 g
Mass of water left in the beaker after the experiment
=
40 g
The percentage of water absorbed by raisins will be
(1) 10%
(2) 25%
(3) 45%
(4) 50%

Answer 1

Answer:

45%

Explanation:

I guess so......

if my answers wrong....tell anyone...even I have doubt on this..ok..

Answer 2

Answer:

The answer is the 4th one which is 50% according to the formula

Explanation:

formula= final weight-initial weight/initial weight into 100 (/ means divide)

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if any doubt, you can ask me.