The following diagram indicates the energy levels of a
certain atom when the system moves from 2 E level to
E, a photon of wavelength is emitted. The
wavelength of photon produced during its transition
from 4E/3
level to E
is
(1) lambda/3
(2) 3lambda/4
(3) 4lambda/3
(4) 3lambda
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Answer:
(4) 3lambda
Explanation:
∆E = E2- E1 = hc/lambda
lambda = hc/∆E
case 1 : ∆E = 2E - E = E
hence lambda = hc/E
now case 2 : ∆E = 4E/3 - E =E/3
hence lambda' = hc/(E/3)
now, lambda'/ lambda = 3
therefore lambda' = 3×lambda
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