Physics, asked by lordhari387267, 1 day ago

The following diagram shows that a simple pendulum consisting of a bob of mass 100 gram. Initially the bob of pendulum is at rest at 'O' it is then displaced to one side at 'A'. The height of 'A' above 'O' is 5 cm (take g=10m/sec²)
What is the value of potential energy of bob at 'A'
What is the value of total (Kinetic energy + Potential energy) at P?

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Answers

Answered by ayushrealme12
1

Answer:

Given:

mass = 100 g = 0.1 kg

g = 10 m/s^{2}s

2

height of A above O = 5 cm = 0.05 m

To find :

a) Potential energy at 'A' and where does it come from.

b) Total energy at 'A'.

c) Kinetic energy at mean position.

d) Kinetic energy and potential energy of the bob at position whose height above is 2 cm.

Solution:

(a) The value of potential energy of the bob at 'A' = m * g * h

= 0.1 * 10 * 0.05 = 0.05 J

It is stored due to the work done on it for raising .

(b). The value of total energy of the bob at position 'A' = P.E. + K.E.

= 0.05 + 0 = 0.05 J

(c). At mean position , total P.E. change to K.E.

So , kinetic energy of the Bob at mean position = 0.05 J

(d). P.E. at 2 m height = m * g * h

= 0.1 * 10 * 0.02 = 0.02 J

K.E. at 2 m height = total energy - P.E. at 2 m height

= 0.05 - 0.02

= 0.03 J

Potential energy at 'A' is 0.05 J and it is stored due to the work done on it .

Total energy at 'A' is 0.05 J .

Kinetic energy at mean position is 0.05 J .

Kinetic energy is 0.03 J and potential energy of the bob is 0.02 J at position whose height above is 2 cm.

Answered by lalitbro
1

Kinetic energy is 0.03 J and potential energy of the bob is 0.02 J at position whose height above is 2 cm.

Given:
Mmass = 100 g = 0.1 kg
g = 10 m/

Height of A above O = 5 cm = 0.05 m

To find :

a) Potential energy at 'A' and where does it come from.

b) Total energy at 'A'.

c) Kinetic energy at mean position.

d) Kinetic energy and potential energy of the bob at position whose height above is 2 cm.

Solution:

Simple pendulum relations:

A natural something used to measure heaviness is a machinelike composition that illustrates periodic motion. The natural device that tells time encompasses a limited jounce of bulk ‘m’ pensile by a thin series obtained to a platform at allure superior end of time L.The plain device that tells time is a machinelike order that sways or moves in an oscillatory motion.

This motion happens in a upright plane and is mainly compelled for one gravitational force. Interestingly, the hop namely postponed last of a fiber very light kind of we can reply it is even massless. The period of a natural device that tells time maybe fashioned widespread by growing the distance strand while communicable the measurements from the point of delay to the middle of the jounce.

(a) The value of potential energy of the bob at 'A' =m * g * h\\                                                                                = 0.1 * 10 * 0.05 = 0.05 J

 It is stored due to the work done on it for raising .

(b).  The value of total energy of the bob at position '
A' = P.E. + K.E.                                                                                         = 0.05 + 0 = 0.05 J

(c). At mean position , total P.E. change to K.E.

 So , kinetic energy of the Bob at mean position = 0.05 J

(d). P.E. at 2 m height  
= m * g * h\\                                           = 0.1 * 10 * 0.02 = 0.02 J

    K.E. at 2 m height = total energy - P.E. at 2 m height

                                   = 0.05 - 0.02                                    = 0.03 J

Potential energy at 'A' is 0.05 J and it is stored due to the work done on it .

Total energy at 'A' is 0.05 J .

Kinetic energy at mean position is 0.05 J .

Kinetic energy is 0.03 J and potential energy of the bob is 0.02 J at position whose height above is 2 cm.

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