Question

The following distribution shows the daily pocket allowance of children of a locality.
The mean pocket allowance is Rs 18. Find the missing frequency f.​

Answer 1

Answer:

Lets take assumed mean, A as 16

Class interval =2

∴u

i

=

h

x

i

−A

=

2

x

i

−16

Now, we have A=16,

x

ˉ

=18 and h=2

We know that,

Mean,

x

ˉ

=A+h(

N

1

∑f

i

u

i

)

⇒18=16+2(

f+44

2f+24

)

⇒

f+44

2f+24

=1

⇒f+44=2f+24

⇒f=20

Hence, the value of missing frequency, f=20

solution