Question

The following electric items are used daily in a house: 1 TV (100 W) for 2 hours,
1 refrigerator (120 W) for 24 hours, 3 fluorescent tubes (40 W) for 4 hours, 2 bulbs (60 W
each) for two hours and 1 electric iron (1000 W) for hour. Determine the electric bill of
and
1
2​

Answer 1

Answer:

388.8 Rs

Explanation:

for television

power,p-100W

time,t-2 hours

electrical energy consumed=P×t

=100W×2h

=200Wh

=0.2k Wh

For fridge

p=120W

t=24hrs

Electrical energy consumed=p×t

=120W×24hrs

=2880Wh

=2.9 k Wh

For fluorescent tubes

p=40W

t=4hrs

Electrical energy consumed=p×t

=40W×4h

=160Wh

=0.16Wh

For three tubes, the electrical energy consumed=3×0.16k Wh

=0.48k Wh

For bulbs

P=60W

T=2hrs

Electrical energy consumed=P×t

=1000W×0.5

500Wh

0.5k Wh

Total energy consumed=0.2k Wh+2.9k Wh+0.48k Wh+0.24k Wh+0.5k Wh

=4.32 k Wh

For one month total energy consumed=4.32×30

=129.6k Wh

Total cost=129.6×3.00

=388.8 Rs.