Question

• The following equation gives a relation between the mass m1 , kept on a surface of area A, and
the pressure P exerted on this area.
P=(m1+m2)x/A
What must be the dimensions of the
Quantities x and m2​

Answer 1

https://chat.whatsapp.com/FW5hkxn2ynELjqK1h0yWFh

Answer 2

Solution:

Given :

→ P = [(m1 + m2)x]/A

Let,

• Z = m1 + m2

Using principal of homogeneity,

[m1] = [m] = [m2] = [m1 + m2]

Dimensional equation :

[P] = [ML^(-1) T^(-2)]

→ [P] = [M][x]/[L²]

→ [x] = [ML^(-1) T^(-2)][L²]/[M]

→ [x] = [LT^(-2)] → Acceleration

Hence,

•Dimension of m2 is [M]

• Dimension of x is [LT^(-2)]