Chemistry, asked by Rohit18168920, 11 months ago

The following equations are balanced atomwise and chargewise.
(i) Cr2O27+8H++3H2O2→2Cr3++7H2O+3O2Cr2O72+8H++3H2O2→2Cr3++7H2O+3O2
(ii) Cr2O27+8H++5H2O2→2Cr3++9H2O+4O2Cr2O72+8H++5H2O2→2Cr3++9H2O+4O2
(iii) Cr2O27+8H++7H2O2→2Cr3++11H2O+5O2Cr2O72+8H++7H2O2→2Cr3++11H2O+5O2
The precise equation/equations representing the oxidation of H2O2H2O2 is/are :

Answers

Answered by keerthana3724

1

Explanation:

cr2027+8h +7h 202- 2cr3+11h20+502

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