The following figure shows a brick of weight 2 N and dimensions 20cm x 10cm x 5cm placed in three different positions on the ground. Find the pressure exerted by the brick in each case
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Answer:
1st case, 1000 pa
2nd case, 4000 pa
3rd case, 2000 pa
Explanation:
We know that P= A/F
, here A=effective area
In first case , P= A/m = 0.1×0.2/2×10
=1000Pa
In second case , P= 0.05×0.1/2×10
=4000Pa
In third case , P= 0.05×0.2/2×10
=2000Pa
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