Question

The following figure shows a circle with centre O If OP is perpendicular to AB prove that AP=BP

Answer 1

AB is the chord of the circle.
join A and B to O

in triangle APO and BPO

AO = BO (radii of the same circle)

<APO = <BPO (given OP ⊥ AB)
OP = OP (common side)
therefore two triangles are congruent by SAS congruency

AP = BP (cpct)

Answer 2

Step-by-step explanation:

THANK YOU

HAVE A GOOD DAY