The following figure shows a closed victory - stand whose dimension are given in centimetres. Find the volume and the surface area of the victory stand.
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Solution :-
Total surface area of the cuboid = 2(L*B + B*H + H*L)
Figure 1 -
Length = 40 cm, Breadth = 30 cm and Height = 30 cm
TSA = 2(40*30 + 30*30 + 30*40)
= 2*(1200 + 900 + 1200)
= 2*3300
= 6600 sq cm
Figure 2 -
Length = 40 cm, Breadth = 30 cm and Height = 30 cm
TSA = 2(40*30 + 30*30 + 30*40)
= 2(1200 + 900 + 1200)
= 2*3300
= 6600 sq cm
Figure 3 -
TSA = 2(40*30 + 30*20 + 20*40)
= 2(1200 + 600 + 800)
= 2*2600
= 5200 sq cm
TSA of Victory Stand = 6600 + 6600 + 5200
= 18400 sq cm
Volume of Cuboid = L*B*H
Figure 1 -
Volume = 40*30*30
= 36000 cu cm
Figure 2 -
volume = 40*30*30
= 36000 cu cm
Figure 3 -
Volume = 40*30*20
= 24000 cu cm
Total volume of the Victory Stand = 36000 + 36000 + 24000
= 96000 cu cm
So, TSA of the Victory Stand is 18400 sq cm and Volume of the Victory Stand
is 96000 cu cm
Answer.
Total surface area of the cuboid = 2(L*B + B*H + H*L)
Figure 1 -
Length = 40 cm, Breadth = 30 cm and Height = 30 cm
TSA = 2(40*30 + 30*30 + 30*40)
= 2*(1200 + 900 + 1200)
= 2*3300
= 6600 sq cm
Figure 2 -
Length = 40 cm, Breadth = 30 cm and Height = 30 cm
TSA = 2(40*30 + 30*30 + 30*40)
= 2(1200 + 900 + 1200)
= 2*3300
= 6600 sq cm
Figure 3 -
TSA = 2(40*30 + 30*20 + 20*40)
= 2(1200 + 600 + 800)
= 2*2600
= 5200 sq cm
TSA of Victory Stand = 6600 + 6600 + 5200
= 18400 sq cm
Volume of Cuboid = L*B*H
Figure 1 -
Volume = 40*30*30
= 36000 cu cm
Figure 2 -
volume = 40*30*30
= 36000 cu cm
Figure 3 -
Volume = 40*30*20
= 24000 cu cm
Total volume of the Victory Stand = 36000 + 36000 + 24000
= 96000 cu cm
So, TSA of the Victory Stand is 18400 sq cm and Volume of the Victory Stand
is 96000 cu cm
Answer.
Yesthat:
its wrong
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