Question

The following frequency distribution represents the deposits in thousand rupees) and the number of depositors in a bank. Find the median of the data :
Deposit (Rs. in thousand)
0-10
10-20
20-30
30-40
40-50
50-60

Number of depositors
1071
1245
150
171
131
8

Answer 1

Deposit (Rs.) ______Number of depositor____Cumulative Frequency

0-10 _________________1071 _______________ 1071

10-20 _______________1245_________________2316

20-30 _______________ 150 ________________2466

30-40 ________________171________________2637

40-50 ________________131________________2768

50-60 ______________ 8_________________2776

To find median class:

Total number of depositor n = 2776

n/2 = 2776/2 = 1388

The class having nearby CF is the median class = 10-20

Median = l+ $(\frac{n/2 -cf}{f} ) h$

l = lower limit of median class = 10

h = class size = 10

cf = CF of class interval preceding the median class = 1071

f = frequency of median class = 1245

n= 2776

Median = 10+ $(\frac{1388-1071{1245} ) 10$

Median = 10+ 3170/1245

= 10+ 2.54

= 12.54

Median of the given data is 12.456 k rupees

or 12.456 ×1000 (∴ rupees are in thousand)

= 12546.18 Rupees

Median = 12546.18 Rupees

Hope it helps you.

Answer 2

Answer:

Above Answer Is Correct....