The following frequency distribution shows the distance (in metres) thrown by 68 students in a Javelin throw competition. Distance (in m) 0–10 10–20 20–30 30–40 40–50 50–60 60–70 Number of students 4 5 13 20 14 8 4 Draw a less than type Ogive for the given data and find the median distance thrown using this curve.
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Answered by
199
Answer-
Less Than No. of cumulative students
10 4
20 5
30 13
40 20
50 14
60 8
70 4
Now
Less Than No. of cumulative students
10 4
20 9
30 22
40 42
50 56
60 64
70 68
Median distance is value of X that corresponds to cumulative frequency
∑∫i = 68
so N = 68
N/2 = 68/2 = 34
We draw a parallel line to X-axis where
no. of student = 34 m
Where line intersect curve at X-axis, it is median,
Median distance = 36 m
For details see attached graph
Less Than No. of cumulative students
10 4
20 5
30 13
40 20
50 14
60 8
70 4
Now
Less Than No. of cumulative students
10 4
20 9
30 22
40 42
50 56
60 64
70 68
Median distance is value of X that corresponds to cumulative frequency
∑∫i = 68
so N = 68
N/2 = 68/2 = 34
We draw a parallel line to X-axis where
no. of student = 34 m
Where line intersect curve at X-axis, it is median,
Median distance = 36 m
For details see attached graph
Attachments:
Janeiro:
Right
Answered by
14
Answer:
Step-by-step explanation:
Median distance is value of x that corresponds to
Cumulative frequency N/2 = 68/2 = 34
Therefore, Median distance = 36 m
Attachments:
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