Question

The following graph represents the change in velocity (magnitude of velocity) of a bus with respect to time:
a. Calculate the total distance covered by the bus in 0 s-10 s.
b. Calculate the acceleration of the bus between 7s - 10s.

Answer 1

Explanation:

Total Distance Travelled = Area under the slope of the graph

                                         = Area of Δ + Area of Rectangle + Area of Trapezium

                                            + Area of Δ

                                          $=\frac{4\times3}{2} + 2\times 3 + \frac{1(3+6)}{2} + \frac{3\times 6}{2} \\\\= 6+6+4.5+9\\\\=25.5 \: m$

Acceleration in 7 s - 10 s is negatives ince the slpoe is going downwards.

$Acceleration = \frac{Slope \ of \ the \ graph}{Time \ taken} \\\\a = \frac{0-6}{10-7} = \frac{-6}{3} =-2 \ m/s^2$