Question

The following information relates to the age of death of 50 persons in an area :

36, 48, 50, 45, 49, 31, 50, 48, 42, 57

43, 40, 32, 41, 39, 39, 43, 47, 45, 52

47, 48, 53, 37, 48, 50, 41, 49, 50, 53

38, 41, 49, 45, 36, 39, 31, 48, 59, 48

37, 49, 53, 51, 54, 59, 48, 38, 39, 45

If the class intervals are 31-33, 34-36, 37-39, …. Then the percentage frequencies for the

last five class intervals are​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answer 2

Step-by-step explanation:

they asked about LAST FIVE class interval

31-33

34-36

37-39

40-42

43-45

46-47

48-50

51-53

54-56

57-59