Math, asked by mrsinghave7630, 1 month ago

the following is a pairs of linear equations in two varibles 4x+ky-5=0

Answers

Answered by chagantisisandbro
0

Answer:

Consider the given equations.

4x+ky+8=0 ……. (1)

2x+3y+7=0 …… (2)

The general equations,

a

1

x+b

1

y+c

1

=0

a

2

x+b

2

y+c

2

=0

Therefore,

a

1

=4,b

1

=k,c

1

=8

a

2

=2,b

2

=3,c

2

=7

Since, the condition of unique solution is

a

2

a

1

=

b

2

b

1

Therefore,

2

4

=

3

k

3

k

=2

k

=6

Hence, k is any real number except 6.

Step-by-step explanation:

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