Question

the following is the data of a pocket expenditure per week of a 50 student in a class it is known that the median of the distribution of rupees 120 find the missing frequency​

Answer 1

Answer:

Step-by-step explanation:

Given The following is the data of a pocket expenditure per week of a 50 student in a class it is known that the median of the distribution of rupees 120 find the missing frequency

The following data is as follows.

Expenditure                   0 – 50  50 – 100  100 – 150  150 – 200  200 – 250

Number of students           7            ?              15                ?               3

 C I                  f               cf

0 – 50                7               7

50 – 100             x               7 + x

100 – 150           15             22 + x

150 – 200           y               22 + x + y

200 – 250           3                25 + x + y

N = 50

So a1 = N/2 = 50/2 = 25 So 25 + a + b = 50

or a + b = 25 ---------1

Q2 = L1 + a2 – c (L2 – L1) / f

120 = 100 + 25 – (7 + a) (150 – 100) / 15

120 = 100 + 25 – 7 – a (50) / 15

120 – 100 = 18 – a (50) / 15

20 = 18 – a (10) / 3

So 18 – a = 6

So a = 12

Now 12 + b = 25

So b = 25 – 12

Or b = 13