Question

The following is the distance - time table of a moving car
Time
10:05 am 0 Km
10:25 am 5 km
10:40 am 12 km
10:50 am 22 km
11:00 am 26 km
11:10 am 28 km
11:25 am 38 km
11:40 am 42 km
ii) When was the car travelling with the greatest speed?
iii) What is the average speed of the car?
iv) What is the speed between 11:25am and 11:40am?
v) During a part of the journey, the car was forced to slow down to 12 Km/h. At what distance did this happen

Answer 1

Answer:

(ii) The car is travelling the greatest speed between 10:40 am to 10:50 am as during this time the distance time graph has maximum slope

(iii) Total distance covered= 42km

Total time taken= 1.58 hour

Average speed= 42/1.58= 26.58km/h

(iv) Speed= Distance/Time taken

42/1hour 35 minutes

42km/95/60hour

42×60/95= 26.52km/h

Sorry I didn't know 5 part

Answer 2

Answer:

This is the distance time graph.

(b)

While moving from A to B,

Speed = (5-0)×60/(25-5) km/h = 15 km/h

While moving from B to C,

Speed = (12-5)×60/(40-25) km/min = 28 km/h

While moving from C to D,

Speed = (22-12)×60/(50-40) km/min = 60 km/h

While moving from D to E,

Speed = (26-22)×60/(60-50) km/min = 24 km/h

While moving from E to F,

Speed = (28-26)×60/(70-60) km/min = 12 km/h

While moving from F to G,

Speed = (38-28)×60/(85-70) km/min = 40 km/h

While moving from G to H,

Speed = (42-38)×60/(100-85) km/min = 16 km/h

Thus, maximum speed was while moving from C to D. This is between 10:40 am and 10:50 am.

(c)

Average speed of the car is = total distance/total time = (42/95) km/min = (42×60/95) km/h = 26.5 km/h

(d)

Speed between 11:25 am and 11:40 am is the speed while moving from G to H,

Speed = 16 km/h

(e)

The car slowed down to 12 km/h during the time 11:00 am and 11:10 am. This happened at a distance 28 km from the start.

Hope it helps !!!

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