The following is the line perpendicular to y = -4x+10 and passing through (7,2)
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Answer:
If a line has the equation
y
=
m
x
, we call slope to
m
and whatever perpendicular line to it has then the equation
y
=
−
1
m
x
In our case
y
=
−
7
16
x
, then, the slope is
m
=
−
7
16
, so the perpendicular has slope
m
´
=
−
1
−
7
16
=
16
7
. Our perpendicular line is
y
=
16
7
x
+
b
. But this line passes through
(
5
,
4
)
. Then
4
=
16
7
⋅
5
+
b
. Transposing terms we have
b
=
−
52
7
Finally, perpendicular line equation is
y
=
16
7
x
−
52
7
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