The following is the ‘Receipts and Payment
Account of a charitable Trust for the year 2018:
Rs. Rs.
To Opening
Balance
By Capital
Payment
Cash 1,000 Investment 10,000
Bank 14,00015,000Furniture 4,000
To capital
fund
Clinical
equipment
5,00019,000
Donation for
clinic fund
6,000By revenue
payment
To revenue
receipts
Salaries 6,200
Interest 30,000 Medicines 14,000
Rent 12,000 Scholarships 10,000
Sundries 3,00045,000Printing etc. 800
Travelling 1,00032,000
By balance c/d
Cash 1,600
Bank 13,40015,000
66,000 66,000
Trust fund originally consisted of Building valued
at Rs.1,50,000, 9% Government Securities of the
nominal value of Rs. 3,50,000 (cost Rs.3,20,000)
and the bank balance of Rs.10,000. Bank interest
collectable at the end of the year was Rs.2,500.
Interest accrued on Investments on 1-1-18
Rs. 3,500 and on 31-12-18 Rs. 5,000. The trust
owed suppliers of medicines Rs.1,200 and Rs. 800
respectively on 1-1-18 and 31-12-18. Furniture on
1-1-18 stood at Rs. 3,000 in the books.
You are required to prepare the final accounts of
the Trust for the year 2018 after providing 2½%
depreciation on the book value of the building and
at 20% on other assets.
Answers
Answer:
Given:
Given:
Selling price (S.P.) of a saree = ₹2,600.and
Profit gained by selling = 30%.
\small\underline{\frak{\pmb{ \red{ To \: find : }}}}
Tofind:
Tofind:
The cost price (C.P.) of the saree.
Understanding the concept:
We're given with the selling price and the profit gained by selling a saree. And we're asked to find the cost price of the saree. For finding this, first let's recall the chapter- "Profit and Loss", which we've studied in previous classes!
Cost Price (C.P.) - The price at which an article is purchased is called it's cost price.
Selling Price (S.P.) - The price at which an article is sold is called it's selling price.good
Profit - If the S.P. of an article is greater than its C.P., we say that there is a profit.
Loss - If the S.P. of an article is less than its C.P., we say that there is a loss.
Overheads - All the expenditure incurred on transportation, repairs, etc are categorised as overheads. Overheads are always included in the C.P. of the article.
In this question, we're only going to deal with the first three sub-topics which are mentioned above. Let's start calculating the required answer!
\small\underline{\frak{\pmb{ \red{ Formula \: to \: be \: used:- }}}}
Formulatobeused:−
Formulatobeused:−
\underline{\boxed{\bf{ C.P. = \bigg(\sf\dfrac{100}{100+Gain \: \% \: (or) \: Loss\:\%} \times S.P \bigg)}}}
C.P.=(
100+Gain%(or)Loss%
100
×S.P)
\small\underline{\frak{\pmb{ \red{ Solution: }}}}
Solution:
Solution:
As per the given data, we've all the required values to substitute them in the formula to find
\begin{gathered}\begin{gathered}\begin{gathered} \\ \longrightarrow\tt{ \pink{C.P. = \bigg(\dfrac{100}{100+Gain \: \% \: (or) \: Loss\:\%} \times S.P \bigg)}}\end{gathered} \end{gathered} \end{gathered}
⟶C.P.=(
100+Gain%(or)Loss%
100
×S.P)
S.P. = 2600
Profit % = 30
Now, on substituting these measures,
\begin{gathered}\begin{gathered}\begin{gathered} \\ \longmapsto { \sf{C.P. = \dfrac{100}{100 + 30} \times 2600}} \\ \\ \longmapsto{ \sf{C.P. = \dfrac{100 \times 260 \cancel{0}}{13 \cancel{0}}}} \\ \\ \longmapsto{ \sf{C.P. \dfrac{ \cancel{26000}}{ \cancel{13}} }} \\ \\ \longmapsto \boxed{ \tt{ \pmb { \red{C.P. = 2,000}}}}\end{gathered}\end{gathered} \end{gathered}
⟼C.P.=
100+30
100
×2600
⟼C.P.=
13
0
100×260
0
⟼C.P.
13
26000
⟼
C.P.=2,000
C.P.=2,000
We've obtained the C.P. as ₹2,000. Let's verify it!
\small\underline{\frak{\pmb{ \red{ Verification: }}}}
Verification:
Verification:
To verify, let's ignore the value of S.P. in the formula and insert the obtained C.P. and profit % in it. Then we shall check does the given value of S.P. equals the same that we get here.
\begin{gathered}\begin{gathered}\begin{gathered} \\ \longmapsto { \sf{C.P. = \dfrac{100}{100 + profit \: \%} \times S.P.}} \\ \\ \longmapsto{ \sf{2000 = \dfrac{100}{100 + 30} \times S.P.}} \\ \\ \longmapsto{ \sf{2000 = \dfrac{100}{130} \times S.P. }} \\ \\ \longmapsto{ \sf{2000 \times 130 = 100 \times S.P.}} \\ \\ \longmapsto{ \sf{260000 = 100 \times S.P.}} \\ \\ \longmapsto{ \sf{ \frac{2600 \cancel{00}}{ 1\cancel{00}} = S.P. }} \\ \\ \longmapsto { \underline{ \underline{ \bf{2,600 = S.P.}}}}\end{gathered} \end{gathered} \end{gathered}
⟼C.P.=
100+profit%
100
×S.P.
⟼2000=
100+30
100
×S.P.
⟼2000=
130
100
×S.P.
⟼2000×130=100×S.P.
⟼260000=100×S.P.
⟼
1
00
2600
00
=S.P.
⟼
2,600=S.P.
Since, the S.P. amount is same, our answer is correct!
\begin{gathered}\begin{gathered}\begin{gathered}\\ \therefore\underline{\sf{\pmb{The\:Cost\: Price\:of\:the\:saree\:is\:\pink{2,000/-}.}}}\end{gathered}\end{gathered} \end{gathered}
∴
TheCostPriceofthesareeis2,000/−.
TheCostPriceofthesareeis2,000/−.
_________________________________________
\begin{gathered}\begin{gathered}\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{100+Gain \: \% \: (or) \: Loss\:\%}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered} \end{gathered} < /p > < p > \end{gathered}