Question

the following is the velocity time graph for a moving body find a) velocity with which motion started b) velocity of the body at point C. c) acceleration acting on the body between A and B. d) acceleration acting on the body between B and C

Answer 1

a)acc to graph motion started at 20m/s
b)acc to graph velocity at point c was 40m/s
c)acc acting is v-u/t = 40-20/3=20/3=6.6666
d)acc to graph slope is 0 during b and c means 0 accleration

Answer 2

a) The value of velocity at time t=0 is 20 m/s.
b) At point C, which is at time t=6 s is 40 m/s as shown in plot.
c) Acceleration is defined as rate of change of velocity with time.
So, A = change in velocity between A and B divided by time.
Point A, velocity = 20 m/s, time = 0
Point B, velocity = 40 m/s, time = 3 s
So, acceleration = (40-20)/(3-0) = 6.67 m/s^2.
d) Acceleration = 0