The following picture shows the condition of a plant cell in different solution. Study the picture and identify the solution.
a. A. Hypotonic solution B. hypertonic solution C . Isotonic solution
b. A. Hypertonic solution B Hypotonic solution C. Isotonic solution
c. A. Hypertonic solution B. Isotonic solution C. Hypotonic solution
d. A. Isotonic solution B. Hypertonic solution C. Hypotonic solution
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Answer:
The answer is (c) Hypertonic - Isotonic - Hypotonic
Explanation:
We know that water moves from high to low. In the first case, water moves outside the cell, because the solution is hypertonic, i.e., with less water, and more salts. This results in plasmolysis of the cell.
The cell remains flaccid in the second case. There is no net uptake or release of water. The amount of water remains the same. Thus, the solution is isotonic.
In the third case, turgidity is achieved. This is because the external solution is hypotonic. Thus the cell environment becomes hypertonic in comparison and water moves from higher amount (external) to lower amount (internal) thus resulting in the turgidity of cell.
Therefore, c is the correct answer.
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