Question

The+Following+Process+Has+Been+Used+To+Obtain+Iodine+From+Oil-Field+Brines++In+Calif+Ornaments.+Nai+Agno3-≫Agi+Nano3++2Agi+Fe-≫Fei2+2Ag++2Fei2+3Cl2+-≫2Fecl3+2I2+How+Many+Grams+Of+Agno3+Are+Required+In+The+First+Step+For+Every+254Kgi2+Produced+In+The+Third+Step.

Answer 1

Given:

The following process has been used to obtain iodine from oil-field drines in California.

NaI+AgNO3→AgI+NaNO3  

2AgI+Fe→FeI2+2Ag

2FeI2+3Cl2→2FeCl3+2I2

To find:

How many grams of AgNO3 are required in the first step for every 254kgI2 produced in the third step?

Solution:

The balanced equations:

NaI + AgNO₃ → AgI + NaNO₃ …(1)

2AgI + Fe → FeI₂ + 2Ag …(2)

2FeI₂ + 3Cl₂ → 2FeCl₃ + 2I₂  …(3)

using the equation (3) we get,

mole of I₂/2 = mole of FeI₂/2

mole of FeI₂/1 = mole of AgI/2

mole of AgI/1 = mole of AgNO₃/1

⇒ mole of I₂ = mole of FeI₂

⇒ mole of AgI/2 = mole of AgNO₃/2

⇒ (254 × 10³)/254 = mole of AgNO₃/2

⇒ 2 × 10³  = mole of AgNO₃

⇒ 2 × 10³  = mass of AgNO₃ / molar mass of AgNO₃

∴ The mass of AgNO₃ = 170 × (2 × 10³) = 340 × 10³g

340 × 10³g of AgNO3 are required in the first step for every 254kgI2 produced in the third step.