the following quantum number are possible for how many orbitals:n=3 l=2 m=+2
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n = 3; l = 2 and m = +2 represents one of the 3d orbital with magnetic quantum number +2.
No two orbitals have same magnetic quantum number. Hence the given quantum number is possible for only one orbital and two electrons.
No two orbitals have same magnetic quantum number. Hence the given quantum number is possible for only one orbital and two electrons.
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The following quantum numbers are possible for one orbital.
- There are four quantum numbers- n, l, m, and s
- n, which is the principal quantum number. Its value denotes the shell.
- l, is the azimuthal quantum number. Its value is 0 to n-1.
- l is 0,1,2,3 for s, p, d, and f -subshells respectively.
- s is the spin quantum number, it can be +1/2 or -1/2
- m is the magnetic quantum number, its value is -l to +l.
- As per question, for n = 3, l = 2, m = +2, there will be one orbital 3dx²-dy² orbital of d-subshell.
- Because, as its n =2, and l = 2 that means it belongs to the 3d-subshell.
- And, a d-subshell has 5 orbitals that are dxy, dyz, dxz, dx²-dy², and dz².
- m = -2, -1, 0, +1, +2 for dxy, dyz, dxz, dz², and dx²-dy² respectively.
- As, m = +2 is the value for 3dx²-dy² orbital.
- Therefore, for n =3, l =2, m = +2, there is only one orbital i.e. 3dx²-dy² orbital.
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