Biology, asked by peterparker20, 3 months ago

The following reaction is a/an
Ba(OH)2 + H2SO4 → BaSO4 + 2H2O
(A) Inorganic chemical reaction
(B) Physical process
(C) Organic chemical reaction
(D) Both A and C​

Answers

Answered by krithikasmart11
0

Answer:

Option (A) Inorganic Chemical Reaction.

Explanation:

Given,

Chemical Reaction: Ba(OH)2 + H2SO4 → BaSO4 + 2H2O

To Find,

The type of chemical reaction.

So,

In the above reaction, BaSO4 and water are the end products. Sulphuric acid reacts with barium hydroxide to form barium sulphate and water.

Concept:

This is an Acid-Base reaction where, Ba(OH)2 is a base and H2SO4 is an acid. This is also known as Acid-Base Neutralization.

Now,

In the given reaction, BaSO4 precipitates out, so Ba2+,SO42− can't be spectator ions. Also, H2O has a very low dissociation contant (KW=10−14, at 25°C), so it can't dissociate into ions. Hence, H+,OH− are too not the spectator ion. Therefore, this reaction has no spectator ion and hence H2O will be included in the ionic reaction, which is given as:

Ba2++2OH−+2H++SO42−⟶BaSO4(s)+2H2O(l)

Therefore, option (A) inorganic chemical reaction is the correct answer.

#SPJ3

Answered by nafibarli789
0

Answer:

Ba(OH)2 + H2SO4 → BaSO4 + 2H2O is an (A) Inorganic chemical reaction.

Explanation:

This is an Acid-Base reaction where Ba(OH)2 exists as a base and H2SO4 stands as an acid. This exists also known as Acid-Base Neutralization.

Now,

In the above reaction, BaSO4 and water stand as the end products. Sulphuric acid reacts with barium hydroxide to form barium sulfate and water.

In the given reaction, BaSO4 precipitates out, so Ba2+, SO42− can't be spectator ions. Also, H2O includes a very low dissociation constant (KW=10−14, at 25°C), so it can't dissociate into ions. Therefore, H+, and OH− are too not the spectator ion. Therefore, this reaction includes no spectator ion and hence H2O will be included in the ionic reaction, which is provided as:

Ba2++2OH−+2H++SO42−⟶BaSO4(s)+2H2O(l)

Therefore, option (A) inorganic chemical reaction exists as the proper answer.

#SPJ3

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