Question

the following reaction kc= 4 at a certain temperature 2NOCL= 2NO(g)+CL2(g) what concentration of NOCL must be put into 4 litre vessel at the start so at equilibrium concentration of NOCL will be 1 M​

Answer 1

The concentration of NOCl is 3.52

Step by step explanation:

The given chemical reaction is as follows.

                   $\bold{2NOCl(g)\leftrightharpoons 2NO(g)+Cl_{2}(g)}$

Initial             y                          0           0

Change        -2x                     +2x          x

Final              1.00                   2x           x

The equilibrium expression of the reaction is as follows.          

$\bold{K_{c}=\frac{[NO]^{2}[Cl_{2}]}{[NOCl]^{2}}}$

Substitute the given values in the equilibrium expression.

$\textrm{4=\frac{(2x)^{2}(x)}{1}}$${4=\frac{(2x)^{2}(x)}{1}$

x = 1.26

From the given,

The equilbrium concentration of NOCl is 1.00

y-2x = 1.00

Substitute the "x" value

y - 2(1.26) = 1.00

y = 3.52 mol

Therefore, NOCl concentration is 3.52 mol.

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