The following represents a sequence of radioactive decays involving two α-particles and one
β-particle.
217At 85 V W X
α α β
What is the nuclide X?
A At 213
85 B r
215
77
I C Pb 209
82 D Tl
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Option (C) 209 Pb 82
Because after two alpha decay the mass will decrease by 8(217-8=209) and atomic number will decrease by 4(85-4=81). And after 1 beta decay,though it depends which type of beta decay it is but bu the options we can decide about it. And in this it is -ve Beta decay. So atomic number increases by 1 and there is no change in mass. So atomic number after beta decay is 82. Hence option (C) is correct.
Because after two alpha decay the mass will decrease by 8(217-8=209) and atomic number will decrease by 4(85-4=81). And after 1 beta decay,though it depends which type of beta decay it is but bu the options we can decide about it. And in this it is -ve Beta decay. So atomic number increases by 1 and there is no change in mass. So atomic number after beta decay is 82. Hence option (C) is correct.
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Because after two alpha decay the mass will decrease by 8(217-8=209) and atomic number will decrease by 4(85-4=81). And after 1 beta decay,though it depends which type of beta decay it is but bu the options we can decide about it. And in this it is -ve Beta decay. So atomic number increases by 1 and there is no change in mass. So atomic number after beta decay is 82. Hence option (C) is correct.