Chemistry, asked by jashmotwani, 4 months ago

The following sequence of reactions occurs in the commercial production of aqueous nitric acid: 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l)ΔH=−907kJ 2NO(g)+O2(g)⟶2NO2(g)ΔH=−113kJ 3NO2+H2O(l)⟶2HNO2(aq)+NO(g)ΔH=−139kJ Determine the total energy change for the production of one mole of aqueous nitric acid by this process.​

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Answered by laughingking777
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The following sequence of reactions occurs in the commercial production of aqueous nitric acid: 4NH3(g)+5O2(g)⟶4NO(g)+6H2O(l)ΔH=−907kJ 2NO(g)+O2(g)⟶2NO2(g)ΔH=−113kJ 3NO2+H2O(l)⟶2HNO3(aq)+NO(g)ΔH=−139kJ Determine the total energy change for the production of one mole of aqueous nitric acid by this process

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