Question

the following shows quadrilateral drawn in the coordinate plane find the area of the quadrilateral

please provide step by step solution ​

Answer 1

hey mate!

Area of the figure = Area of ∆ ABC + Area of ∆ ADC

= 1/2 × base × height 1 + 1/2 × base × height 2

$= \frac{1}{2} \times 8 \times 6 + \frac{1}{2} \times 8 \times 1$

$= 4 \times 6 + 4 \times 1$

$= 24 + 4$

$= 28 \: sq \: units$

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