CBSE BOARD X, asked by shwetanair0202, 6 months ago

the following system of equations determine whether the system has unique solution no solution or infinitely many solution in each case if there is a unique solution find it.
 - 3x +4y = 5
3x - 6y + (15  \div 2) = 0

Answers

Answered by shubhda86
0

In the following system of equation determine whether the system has a unique solution, no solution or infinitely many solutions. In case there is a unique solution, find it.

−3x+4y=5

2

9

x−6y+

2

15

=0.

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ANSWER

The given system of equations may be written as

−3x+4y−5=0

2

9

x−6y+

2

15

=0

The given system of equations is of the form

a

1

x+b

1

y+c

1

=0

a

2

x+b

2

y+c

2

=0

where, a

1

=−3,b

1

=4,c

1

=−5 and a

2

=

2

9

,b

2

=−6,c

2

=

2

15

We have,

a

2

a

1

=

9/2

−3

=

3

−2

,

b

2

b

1

=

−6

4

=

3

−2

and

c

2

c

1

=

15/2

−5

=

3

−2

Clearly,

a

2

a

1

=

b

2

b

1

=

c

2

c

1

So, the given system of equations has infinitely many solutions.

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