CBSE BOARD X, asked by shwetanair0202, 11 months ago

the following system of equations determine whether the system has unique solution no solution or infinitely many solution in each case if there is a unique solution find it.
 - 3x +4y = 5
3x - 6y + (15  \div 2) = 0

Answers

Answered by shubhda86
0

In the following system of equation determine whether the system has a unique solution, no solution or infinitely many solutions. In case there is a unique solution, find it.

−3x+4y=5

2

9

x−6y+

2

15

=0.

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ANSWER

The given system of equations may be written as

−3x+4y−5=0

2

9

x−6y+

2

15

=0

The given system of equations is of the form

a

1

x+b

1

y+c

1

=0

a

2

x+b

2

y+c

2

=0

where, a

1

=−3,b

1

=4,c

1

=−5 and a

2

=

2

9

,b

2

=−6,c

2

=

2

15

We have,

a

2

a

1

=

9/2

−3

=

3

−2

,

b

2

b

1

=

−6

4

=

3

−2

and

c

2

c

1

=

15/2

−5

=

3

−2

Clearly,

a

2

a

1

=

b

2

b

1

=

c

2

c

1

So, the given system of equations has infinitely many solutions.

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