Question

The following table gives distribution of wages of 100 workers:

wages :120-140 140-160 160-180 180-200 200-220 220-240 240-260
no.of workers :9 20 0 10 8 35 18


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Answer 1

Answer:

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Step-by-step explanation:

Mean=

f

i

∑f

i

x

i

=

50

7260

=145.2

⇒ We have, N=50. Then,

2

N

=25.

⇒ Median class is 120−140

l= lower limit of the modal class

h= size of the class intervals

f= frequency of the modal class

f

1

= frequency of the class preceding the modal class

f

2

= frequency of the class succeed in the modal class.

⇒ So, l=120,h=20,N=50cf=12,f=14.