Question

The following table gives the lengths of 62 leaves of a plant in mm. Represent the data by a histogram Length. no of leaves 150-153. 7 154-157. 7 158-161. 15 162-165. 10 ​

Answer 1

Answer:

Length

(in mm) New length

(in mm) No. of leaves

118 - 126 117.5 - 126.5 3

127 - 135 126.5 - 135.5 5

136 - 144 135.5 - 144.5 9

145 - 153 144.5 - 153.5 12

154 - 162 153.5 - 162.5 5

163 - 171 162.5 - 171.5 4

172 - 180 171.5 - 180.5 2

In order to make a histogram, we need to convert discontinuous classes to continuous classes.

Adjustment =

2

1

(lower limit of class - upper limit of previous class)

=

2

1

(127−126)=0.5

So, 0.5 needs to be subtracted from upper limit of previous class and lower limit of next class.

(ii) Frequency polygon

(iii) No. It is a range. The maximum number of leaves lies in between 144.5mm−154.5mm. Not necessary that it all occurs as 153mm length.

solution