Math, asked by BrainlyHelper, 1 year ago

The following table gives the number of children of 150 families in a village
No of children (x): 0 1 2 3 4 5
No of families (f): 10 21 55 42 15 7

Find the average number of children per family.

Answers

Answered by nikitasingh79
42

ASSUMED MEAN METHOD :  

In this method, first of all, one among xi 's is chosen as the assumed mean denoted  by ‘A’. After that the difference ‘di’ between ‘A’ and each of the xi's i.e di = xi - A is calculated .  

ARITHMETIC MEAN =  A +  Σfidi / Σfi

[‘Σ’ Sigma means ‘summation’ ]

★★ We may take Assumed mean 'A’ to be that xi which lies in the middle of x1 ,x2 …..xn.

FREQUENCY DISTRIBUTION TABLE IS IN THE ATTACHMENT  

From the table : Σfidi = - 98 ,Σfi = 150 , A = 3

ARITHMETIC MEAN =  A +  Σfidi / Σfi

ARITHMETIC MEAN =  3 + (- 98/150)

= 3 -  98/150

= 3 -  49/75

= 3 - 0.653

= 2.347

ARITHMETIC MEAN = 2.347 ≈ 2.35 (approximate)  

Hence, the average number of children per family is ≈ 2.35(approximate).  

HOPE THIS ANSWER WILL HELP YOU….

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Answered by Anonymous
71

Answer :

The average number of children per family is 2.35 .

Step-by-step explanation :

Assumed mean method -

In assumed mean method, at first one of the x_{i} is chosen as assumed mean which is denoted by "A".

Then we calculate the difference, d_{i} by using the given formula i.e.,

d_{i}=x_{i}-A  

Arithmetic\:mean=A+\frac{\Sigma f_{i}d_{i}}{\Sigma f_{i}}

where \Sigma means summation.

Let us take the assumed mean to be 3.

Frequency Distribution Table -

\begin{tabular}{| c | c | c | c |}\cline{1-4}x_i & f_i & d_i=x_{i}-A & f_{i}d_{i} \\ \cline{1-4}0 & 10 & -3 & -30 \\ \cline{1-4}1 & 21 & -2 & -42 \\ \cline{1-4}2 & 55 & -1 & -55 \\ \cline{1-4}3 & 42 & 0 & 0 \\ \cline{1-4}4 & 15 & 1 & 15 \\ \cline{1-4}5 & 7 & 2 & 14 \\ \cline{1-4} & \Sigma f_{i}=150 & & \Sigma f_{i}d_{i}=-98\\ \cline{1-4}\end{tabular}

Since, Arithmetic mean -

\implies A+\frac{\Sigma f_{i}d_{i}}{\Sigma f_{i}}

\implies 3+\frac{(-98)}{150}

\implies 3-\frac{98}{150}

\implies 3-\frac{49}{75}

\implies 3-0.653

\implies 2.347

\implies \approx 2.35

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