The following table shows current in
Amperes and potential difference in
b. What will be the nature of the graph
between the current and potential
difference? (Do not draw a graph.)
c. Which law will the graph prove?
Explain the law.
Volts.
a. Find the average resistance.
V (Volts) I (Amp)
4
9
5
11.25
13.5
6
Answers
Answered by
0
Answer:
x
2
×x
6
=x
2+6
=x
8
{x}^{5} \div {x}^{3} = {x}^{5 - 3} = {x}^{2}x
5
÷x
3
=x
5−3
=x
2
{( {x}^{2} })^{4} = {x}^{8}(x
2
)
4
=x
8
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