Question

the following table shows the number of employees in a company and their ages find the mode of the ages

Answer 1

the answer will be 47.142 as shown by me in the above questions

Answer 2

Answer:

The mode of the ages is 47.14

Step-by-step explanation:

Explanation:

From the given table we see that the heighest frequency is 9 .

So, $f_{1}$ = 9  , $f_{0}$= 6 , and $f_{2}$ = 5

and at the centre of the heighest value  of frequency we get the class interval which is 45-50.

There fore ,

lowest value (l)= 45

difference between of class interval (h) = 5

Step 1:

Here we know that ,

The formula of Mode = $l + \frac{f_{1} -f_{0} }{(2f_{1} -f_{0} -f_{2} )} h$

Put the value of $l , h , f_{0}, f_{1}and f_{2}$  in the given formula .

∴ Mode = $45+ \frac{(9 -6) }{(18 -6 -5 )} 5$

             = $45+ \frac{(3) }{(7 )} 5$

            = $\frac{(45)(7)+(15)}{7}$

             =  $\frac{(315)+(15)}{7}$

           =   $\frac{(330)}{7}$ = 47.14.

Final answer:

Hence ,the mode of the given table is 47.14.