The following table shows the number of patients of different age groups
admitted to a hospital for treatment on a day. Find the median of ages of
the patients.
Age- group (Yrs.) 10-20 20-30 30-40 40-50 50-60 60-70
No. of patients 40 32 35 45 33 15
Answers
Answer:
38
Step-by-step explanation:
Hi,
Given , data about a total of 200 patients in different age groups ho have
visited the hospital.
If we summarize the given data in the table, along side Less than cumulative frequency
Age-Group No of patients Less than cumulative frequency
10-20 40 40
20-30 32 72
30-40 35 107
40-50 45 152
50-60 33 185
60-70 15 200
Clearly, 100th patient all in the 30-40 Age group,
SO if we consider 30-40 as out median class,
From the formula of median , M = L + (N/2 - C)*w/f where
L = lower boundary of the median class = 30
N = total frequency = 200
C = cumulative frequency of the class preceding the median class = 72
f = frequency of the median class = 35
w = width of the median class i.e. upper boundary - lower boundary = 10
Thus, Median = 30 + (200/2 - 72)*10/35
= 30 + 28*10/35
= 30 + 8
= 38.
Hence, Median of the ages of the patients = 38.
Hope, this helped !
Answer:
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Step-by-step explanation:
Brainly.in
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anildeshmukh
Secondary SchoolMath 5+3 pts
The following table shows the number of patients of different age groups
admitted to a hospital for treatment on a day. Find the median of ages of
the patients.
Age- group (Yrs.) 10-20 20-30 30-40 40-50 50-60 60-70
No. of patients 40 32 35 45 33 15
Ask for details UnfollowReport by EbrainyP 29.12.2018
Answers
anildeshmukh
Anildeshmukh · Ace
Know the answer? Add it here!
VEDULAKRISHNACHAITAN
VEDULAKRISHNACHAITAN Samaritan
Answer:
38
Step-by-step explanation:
Hi,
Given , data about a total of 200 patients in different age groups ho have
visited the hospital.
If we summarize the given data in the table, along side Less than cumulative frequency
Age-Group No of patients Less than cumulative frequency
10-20 40 40
20-30 32 72
30-40 35 107
40-50 45 152
50-60 33 185
60-70 15 200
Clearly, 100th patient all in the 30-40 Age group,
SO if we consider 30-40 as out median class,
From the formula of median , M = L + (N/2 - C)*w/f where
L = lower boundary of the median class = 30
N = total frequency = 200
C = cumulative frequency of the class preceding the median class = 72
f = frequency of the median class = 35
w = width of the median class i.e. upper boundary - lower boundary = 10
Thus, Median = 30 + (200/2 - 72)*10/35
= 30 + 28*10/35
= 30 + 8
= 38.
Hence, Median of the ages of the patients = 38.
Hope, this helped !