Question

The Following Table shows the number of runs scored by Aditya in the last 6 matches that he played. Now answer the following questions.

(I) In which Innings was his batting average better–the first innings or the second?
(II)Did he bat better in the first three matches or the last three matches?
(III)What was Aditya's batting average for the last 6 matches?

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Answer 1

Answer:

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(I) Batting average in the first innings

$= \frac{sum \: of \: the \: first \: innings \: scores}{number \: of \: first \: innings \: played}$

$= \frac{32 + 11 + 0 + 46 + 23 + 14}{6} = \frac{126}{6} = 21$

Batting average in second innings

$= \frac{9 + 28 + 12 + 54 + 13 + 63}{6} = \frac{179}{6} = 29.83$

Thus, Aditya's batting average was better while playing in the second innings.

(II) Average of first 3 matches

$= \frac{total \: runs \: scored \: in \: the \: frst \: 3 \: matches}{3}$

$= \frac{41 + 39 + 12}{3} = \frac{92}{3} = 30.6$

Average of last 3 matches

$= \frac{total \: runs \: scored \: in \: last \: 3 \: matches}{3}$

$= \frac{100 + 36 + 77}{3} = \frac{213}{3} = 71$

Thus, he batted better in the last three matches.

(III) Batting average for the last 6 matches

$= \frac{total \: runs \: scored \: in \: the \: last \: 6 \: matches}{6}$

$= \frac{305}{6} = 50.83$

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•We have seen that:

$average = \frac{sum \: of \: measures \: }{number \: f \: measures}$

The following two formulas can be easily derived from the above formula :

Sum of measures = Average × Number of measures

Number of measures

$= \frac{sum \: of \: measures}{average}$

* The average is also called the mean or the Arithmetic Mean.

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