Question

The following table shows the speedometer
readings of a car:
time speedometer
reading(km/h)
10:25pm 62
10:35pm
74
10:45 pm
90
10:55pm
60
11:05 pm
65
11:15 pm
38
Find the displacement of the car in last 10
minutes of the journey.​

Answer 1

Answer:

no

Explanation:

sorry sorry sorry sorry sorry

Answer 2

Answer:

8500m or 8.5km

Explanation:

for last 10 minutes u=65km/h=65×5/18=18.05m/s

                               v=38km/h=38×5/18=10.55m/s

                              and t= 10mins=10*60=600s

acceleration(a)=(v-u)/t= (10.55-18.05)/600 = -0.0125m/s²

we know that from equations of motion

v²-u²=2as

so, [(10.55)²-(18.05)²]=2×0.0125×s where s is the displacement of the car.

so calculating the displacement of the car by the above formulae we can get the displacement that

s=8500m or else we can write that this as 8.5 km