The following table shows the weight of 12 players : weight-48,50,52,54,58. Number of players - 4,3,2,2,1. Find median and mean weights. Using empirical formula find mode.
Answers
Answer:
meadian = 52
mean=21.8
mode =2
Answer: The mean of the following data is 21.833.
The median of the following data is 49.
The mode of the following data is 103.334.
Step-by-step explanation:
Calculate the commutative frequency: we got; 4,7,9,11,12
To calculate the mean , the formula is :
Mean = sum of weights of players / number of players
Mean= 48+50+52+54+58/12
Mean= 262÷12 = 21.833
Hence, the mean of the following data is 21.833
Now to find median of the following data.
n=12. Hence , it is even and the formula to find median will be:
Median = ((n/2)тн observation +(n/2+1)th observation)/2
Median= ((12/2)th observation+ (12/2+1)th observation)/2
Median=(6th observation +7th observation)/2
Through comutative frequency we can find our 6th observation and 7th observation.
Hence, median= (48+50)/2 = 49
Hence, median of the following data is 49.
Now, emperical formula states that :
Mode= 3median-2mean
So, according to the formula,
Mode=3×49-2×21.833
Mode= 147-43.666
Mode = 103.334
Hence, the mode of the following data is 103.334