The following table shows the weights of 15 students:weight(in kg) 47 50 53 56 60 number of students 4 3 2 2 4.calculate 1.mean 2.median 3.mode. ICSE
Answers
Step-by-step explanation:
Answer:
Mean = 53.067
Median = 53
Mode = 47 and 60 - This data is Bimodal
Step-by-step explanation:
We are given the following data below;
Weight (in Kg) - X No. of students (f) cf X*f
47 4 4 188
50 3 7 150
53 2 9 106
56 2 11 112
60 4 15 240
Mean = \frac{\sum Xf}{\sum f}
∑f
∑Xf
= \frac{796}{15}
15
796
= 53.067
Median is given by;
First we calculate \frac{N}{2}
2
N
, where N = ∑f ⇒ \frac{15}{2}
2
15
= 7.5
Here, value of cf just greater than or equal to 7.5 is 9.
Therefore, Median = 53 because the weight corresponding to cf of 9
is 53.
Mode is the number which appears maximum times in our data.
Here two weights 47 and 60 have the same frequency so we conclude
this data is Bimodal i.e. having two modes.