Question

The following table shows the weights of 15 students:weight(in kg) 47 50 53 56 60 number of students 4 3 2 2 4.calculate 1.mean 2.median 3.mode. ICSE​

Answer 1

Step-by-step explanation:

Answer:

Mean = 53.067

Median = 53

Mode = 47 and 60 - This data is Bimodal

Step-by-step explanation:

We are given the following data below;

Weight (in Kg) - X No. of students (f) cf X*f

47 4 4 188

50 3 7 150

53 2 9 106

56 2 11 112

60 4 15 240

Mean = \frac{\sum Xf}{\sum f}

∑f

∑Xf

= \frac{796}{15}

15

796

= 53.067

Median is given by;

First we calculate \frac{N}{2}

2

N

, where N = ∑f ⇒ \frac{15}{2}

2

15

= 7.5

Here, value of cf just greater than or equal to 7.5 is 9.

Therefore, Median = 53 because the weight corresponding to cf of 9

is 53.

Mode is the number which appears maximum times in our data.

Here two weights 47 and 60 have the same frequency so we conclude

this data is Bimodal i.e. having two modes.