Question

The following values of x and y are thought to satisfy a linear equation, Write the linear equation. Draw the graph, using the values ofx, y as given in the above table. At what point the graph of the linear equation (1 cuts the x-axis. (i) cuts the Y-axis.​

Answer 1

Step-by-step explanation:

The following values of x and y are thought to satisfy a linear equation, Write the linear equation. Draw the graph, using the values ofx, y as given in the above table. At what point the graph of the linear equation (1 cuts the x-axis. (i) cuts the Y-axis.

Answer 2

Step-by-step explanation:

$Let the linear equation y = mx + c satisfies the points (6-2) and (-6,6).</p><p></p><p>- 2 = 6 m+ c...(i) and 6 = -6 m + c... (ii)</p><p></p><p>On subtracting Eq. (ii) from Eq. (i), we get \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ 12m=-8 ⇒m=2 \3 \\ \\ \\ On putting the value of m = - 2 \3 \\ in Eq. (i), we get \\ \\ \\ \\ \\ - 2 = 6( - 2 \3) + c \\ \\ \\ \\ \\ \\ -2=-4+C \\ \\ \\ \\ \\ \\ \\ \\ c = 2 \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ y = - 2 \3x + 2 \\ \\ \\ \\ \\ \\ 3y + 2x = 6 \\ \\ \\ \\ \\ \\ \\ \\ which is the required linear equation and its graph</p><p></p><p>is \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ On putting y=0 in eq.(iii), we get</p><p></p><p>0 + 2x = 6</p><p></p><p>=> X = 3 \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ (3, 0) is a solution of the equation. Again, putting x = 0 in Eq. (iii), we get => y=2 (i) The graph of the linear equation will cut X-axis</p><p></p><p>3y + 0 = 6</p><p></p><p>(0,2) is a solution of the equation.</p><p></p><p>at</p><p></p><p>(3,0).</p><p></p><p>(ii) The graph of the linear equation will cut Y-axis at</p><p></p><p>(0,2).$

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