the following vectors is/are perpendicular to 5k
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Explanation:
(i) If vector A and B are perpendicular,
then, A.B=0
where, (A= a1i+a2j+a3k) and (B=b1i+b2j+b3k)!
1. Let (A=0i+0j+5k) (B=4i+3j+0k),
A.B= [(0)(4)]i+[(0)(3)]j+[(5)(0)]
A.B.= 0
Their vector product is zero
Hence the are perpendicular.
2. Let (A=0i+0j+5k) (B=6i+0j+0k)
A.B=[(0)(6)]i+[(0)(0)]j+[(5)(0)]k
A.B=0
Hence they are perpendicular.
3. Let (A=0i+0j+5k) (B=0i+0j+7k)
A.B=[(0)(0)]i+[(0)(0)]j+[(5)(7)]
A.B=35
Hence they are not perpendicular.
4. Let (A=0i+0j+5k) (B=3i+4j+0k)
A.B=[(0)(3)]i+[(0)(4)]j+[(5)(0)]k
A.B=0
Hence they are perpendicular.
Hope It Helps!
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