Question

The following velocity-time graph
represents a particle moving in the
positive X-direction. Analyse its
motion from 0 to 7 s. Calculate the
displacement covered and distance
travelled by the particle from 0 to 2 s.​

Answer 1

Answer:

Explanation:

Final Answer :

Distance = 7/8 m

Displacement = 5/8m

Steps:

1) Analyzing the Motion from t =0 to t = 7s:

Initially, the speed of particle increases to its maximum value, then again it's value decreases to 0.

=> After that value of speed again increases but in opposite direction, then it remains constant.

After acquiring constant speed, it decreases to 0 and remains 0.

2) Second Part :

Distance covered from t = 0 to t = 2s.

= | Displacement from t = 0 to t = 1.75 s) + | Displacement from t = 1.75 s to t = 2s|

= |Area under v-t in required time interval |

+ | Area under v-t in required time interval ¦

=

Displacement = Area under v-t graph from t = 0 to t = 1.75 s - Area from t = 1.75s to t = 2s