The foot of 10 m long ladder placed against vertical wall is 8 m away from the base of wall. Find the height of the wall. *
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the height of the wall is 6m
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Step-by-step explanation:
Let WA=10m be the length of the ladder and WL=xcm be the height of the wall . As wall WL=xm is vertically up so by Pythagoras theorem.
In right angled triangle WLA
(10)^2 = (8)^2 + (x)^2
100 = 64 + x^2
100- 64 = x^2
36 = x^2
⇒x=6
Hence , the height of the point on the wall where the top of the ladder reaches is 6m.
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